In the differential form, the steady flow energy equation per unit mass is given by
dQ = dh + VDV + gdZ + dWx (1)
For a reversible process, dQ = Tds
Tds = dh + VdV + gdZ + dWx (2)
Using the property relation,
Tds = dh - vdp (3)
From (2) and (3) ,
-vdp = VdV + gdZ + dWx (4)
On Integration
- Integral vdp = delta (V^2 / 2) + g (Delta Z) + Wx (5)
If the changes in K.E and P.E are neglected, (5) reduces to
Wx = - Integral (vdp) (6)
If dQ = 0, implying ds = 0, the property relation gives
dh = vdp
or
h2-h1 = Integral vdp (7)
From Equation (6) and (7)
Wx = h2 - h1 = - Integral vdp (8)
The equation (8) holds good for a steady flow work producing machine like an engine or turbine as well as for a work absorbing machine like a pump or a compressor, when the fluid undergoes reversible adiabatic expansion or compression.
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